Homework 1 ECE4603 Fall'00 Homework Assignment #2 (v.1.0) --------- (You may delete all above this line) ------------------ ***START_HW*** (do not delete preceding flag, or the -XXXX flags below). [ ]-NAME Enter your name (form: last, first middle initial) [ ]-PRISM Enter your Prism account code (form: "gtXNNNA" where "N" is a number, "A" is a letter, and X is either. Do not include "@prism.gatech.edu"). [ ]-EMAIL Enter the email address ("account@server") where you would like to receive your graded homework. If on Prism, you may leave completely blank"). #1. A/D Conversion [ 16,000 ] In order to digitize an analog signal with frequency components from 0 to 8000 Hz, how many time per second would you have to sample the value of the signal (neglect the extra amount needed because filters have a finite roll-off). [ 7 | 8 ] If you wanted to send a binary value of the signal voltage accurate to less than 1% of the peak value (40 dB), how many bits per sample would be required to represent the value. [ 28,000 | 32,000 ] How many bits per second would be transmitted (or stored). #2. According to Nyquist, if a digital encoder can NRZ encode 16 levels per time slot of 100 microseconds, what is the: [ 4 ] Bits per symbol. log2(16) [ 10,000 ] Baud Rate (Baud/s). 1/100E-6 [ 40,000 ] Capacity (bits per second). answer 1 * answer 2 [ 5,000 ] Bandwidth required (Hz). 1/2 answer 2 #3. If a 100,000 Hz baseband digital signal modulates a 1,000,000 Hz carrier wave, what is the [ 200,000 ] - bandwidth of the broadband signal (in Hz). [ 900,000 ] - the lower frequency edge of the broadband signal (in Hz). [ 1,100,000 ] - the upper frequency edge of the broadband signal (in Hz). #4. If the receiver input noise level in an 8-level system is -10 dBm (dB relative to one milliwatt), what is the theoretical (Shannon Limit) minimum power needed at the receiver? [ 6.3 ] Power in milliwatts 8 = sqrt(S/N + 1 ) , S/N = 64 - 1 = 63 63 * 0.1 mW = 6.3 mW [ 8 ] Power in dBm S/N in dB: = 10*log(63) = 18 dB, N = -10 dBm #5. What is the bandwidth (in Hz) needed if 200 Baud per second are transmitted using the following types of modulation: [ 100 ] Two-level NRZ (non-return to zero) F = 0.5 [ 200 ] Two-level RTZ (return to zero) F = 1.0 [ 100 ] Two-level NRZ-I (NRZ inverted) F = 0.5 [ 200 ] Any common type of broadband moduation (ASK, PSK, QPSK, QAM). [ 200 ] Manchester Encoding F = 1.0 #7. What bandwidth (Mhz) is needed to send 1 Mbps in a broadband system using the following modulation techniques: [ 1 ] Two-level amplitude modulation (ASK). F=1.0, 1 bit/Baud [ 0.5 ] Four-level phase-shift keying (PSK) F=1.0 2 bits/Baud [ 0.5 ] Four-level quadrature phase-shift keying (QPSK) " [ 0.25 ] Sixteen-level quadrature amplitude keying (QAM-16) 4 b/B ***END_HW*** (do not delete preceding flag) (1.0 -email)